We provided NCERT Solutions for Class 12 Chemistry Chapter 2 Solutions is prepared by the best teachers across India. These NCERT 12th Class Chemistry Chapter 2 Solutions Solution includes detailed answers of all the questions in Chapter 2 Solutions provided in NCERT Book which is prescribed for Class 12 in CBSE school Books. This will help students to understand basic concepts better.
CBSE NCERT 12th Class Chemistry Chapter 2 Solutions Solutions
| Organisation | National Council of Educational Research and Training |
| Class Name | 12th Class |
| Subject Name | Chemistry |
| Chapter Name | Chapter 2 |
| Content name | Solutions |
| Category Name | CBSE NCERT Solutions |
| Official Website | http://ncert.nic.in/ |
NCERT 12th Class Chemistry Chapter 2 Solutions Solution is given below
| Section Name | Topic Name |
| 2 | Solutions |
| 2.1 | Types of Solutions |
| 2.2 | Expressing Concentration of Solutions |
| 2.3 | Solubility |
| 2.4 | Vapour Pressure of Liquid Solutions |
| 2.5 | Ideal and Non-ideal Solutions |
| 2.6 | Colligative Properties and Determination of Molar Mass |
| 2.7 | Abnormal Molar Masses |
Question 2.23:
Suggest the most important type of intermolecular attractive interaction in the following pairs.
(i) n-hexane and n-octane
(ii) I2 and CCl4
(iii) NaClO4 and water
(iv) methanol and acetone
(v) acetonitrile (CH3CN) and acetone (C3H6O).
Answer
(i) Van der Wall’s forces of attraction.
(ii) Van der Wall’s forces of attraction.
(iii) Ion-diople interaction.
(iv) Dipole-dipole interaction.
(v) Dipole-dipole interaction.
Question 2.24:
Based on solute-solvent interactions, arrange the following in order of increasing
solubility in n-octane and explain. Cyclohexane, KCl, CH3OH, CH3CN.
Answer
n-octane is a non-polar solvent. Therefore, the solubility of a non-polar solute is more than that of a polar solute in the n-octane.
The order of increasing polarity is:
Cyclohexane < CH3CN < CH3OH < KCl
Therefore, the order of increasing solubility is:
KCl < CH3OH < CH3CN < Cyclohexane
Question 2.25:
Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water?
(i) phenol (ii) toluene (iii) formic acid
(iv) ethylene glycol (v) chloroform (vi) pentanol.
Answer
(i) Phenol (C6H5OH) has the polar group −OH and non-polar group −C6H5. Thus, phenol is partially soluble in water.
(ii) Toluene (C6H5−CH3) has no polar groups. Thus, toluene is insoluble in water.
(iii) Formic acid (HCOOH) has the polar group −OH and can form H-bond with water.
Thus, formic acid is highly soluble in water.
(iv) Ethylene glycol has polar −OH group and can form H−bond. Thus, it is highly soluble in water.
(v) Chloroform is insoluble in water.
(vi) Pentanol (C5H11OH) has polar −OH group, but it also contains a very bulky nonpolar −C5H11 group. Thus, pentanol is partially soluble in water.
