We provided NCERT Solutions for Class 12 Physics Chapter 9 Ray Optics and Optical Instruments is prepared by the best teachers across India. These NCERT 12th Class Physics Chapter 9 Ray Optics and Optical Instruments Solution includes detailed answers of all the questions in Chapter 9 Ray Optics and Optical Instruments provided in NCERT Book which is prescribed for Class 12 in CBSE school Books. This will help students to understand basic concepts better.
CBSE NCERT 12th Class Physics Chapter 9 Ray Optics and Optical Instruments Solutions
Organisation | National Council of Educational Research and Training |
Class Name | 12th Class |
Subject Name | Physics |
Chapter Name | Chapter 9 |
Content name | Ray Optics and Optical Instruments |
Category Name | CBSE NCERT Solutions |
Official Website | http://ncert.nic.in/ |
NCERT 12th Class Physics Chapter 9 Ray Optics and Optical Instruments Solution is given below
Section Name | Topic Name |
9 | Ray Optics and Optical Instruments |
9.1 | Introduction |
9.2 | Reflection of Light by Spherical Mirrors |
9.3 | Refraction |
9.4 | Total Internal Reflection |
9.5 | Refraction at Spherical Surfaces and by Lenses |
9.6 | Refraction through a Prism |
9.7 | Dispersion by a Prism |
9.8 | Some Natural Phenomena due to Sunlight |
9.9 | Optical Instruments |
Question 9.1:
A small candle, 2.5 cm in size is placed at 27 cm in front of a concave mirror of radius of curvature 36 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? Describe the nature and size of the image.
If the candle is moved closer to the mirror, how would the screen have to be moved?
Answer
Size of the candle, h = 2.5 cm
Image size = h’
Object distance, u = −27 cm
Radius of curvature of the concave mirror, R = −36 cm